CLIGUI 2024-08-17 22:58 (Edited)
R=0
PRINT R=RND(3999)
PRINT R
TEXT 0,2, ""+STR$(R)+""
NUMBER 15,0,R,5
All four will say R=0, but change the R to 3 and PRINT R=RND(3999) will still say 0.
CLIGUI 2024-08-17 23:08 (Edited)
I thought this was because it would only print if R=0, but this is not the case, because if you change the R in R=RND to another variable it will say R is not initialized.
CLIGUI 2024-08-17 23:16
PRINT RND(9)=0 however will do nothing.
Pablo 2024-08-18 02:20 (Edited)
I rewrote your example to illustrate it's behaviour:
R=0
IF R=RND(3999) THEN
RET = -1
ELSE
RET = 0
END IF
PRINT RET
PRINT R
TEXT 0,2, ""+STR$(R)+""
NUMBER 15,0,R,5was8bit 2024-08-18 04:14
@cligui…
It is because the equation with the = symbol will cause lowresnx to render it as a true/false and therefore yield a true false
Try this…
R=0
PRINT R=RND(3999)
PRINT R
TEXT 0,2, ""+STR$(R)+""
NUMBER 15,0,R,5
PRINT 1=2
PRINT 1=1
PRINT R=R
was8bit 2024-08-18 04:17
You may also do this to temporarily disable a section of code…
IF 0 then
End if
was8bit 2024-08-18 04:19
When you write
IF A=B then
LowRes converts A=B to a 0 or -1
was8bit 2024-08-18 04:21
PRINT (1=1) + (3=3)
Will print
-2